pairs with difference k coding ninjas github

Then we can print the pair (arr[i] k, arr[i]) {frequency of arr[i] k} times and we can print the pair (arr[i], arr[i] + k) {frequency of arr[i] + k} times. This is O(n^2) solution. A tag already exists with the provided branch name. // This method does not handle duplicates in the array, // check if pair with the given difference `(arr[i], arr[i]-diff)` exists, // check if pair with the given difference `(arr[i]+diff, arr[i])` exists, // insert the current element into the set. 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Problem : Pairs with difference of K You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the array's elements. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. HashMap map = new HashMap<>(); System.out.println(i + ": " + map.get(i)); //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). Think about what will happen if k is 0. (5, 2) So we need to add an extra check for this special case. This is a negligible increase in cost. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. A naive solution would be to consider every pair in a given array and return if the desired difference is found. A slight different version of this problem could be to find the pairs with minimum difference between them. Ideally, we would want to access this information in O(1) time. Following is a detailed algorithm. The algorithm can be implemented as follows in C++, Java, and Python: Output: This website uses cookies. return count. It will be denoted by the symbol n. Instantly share code, notes, and snippets. Learn more. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. 2. Therefore, overall time complexity is O(nLogn). The idea is that in the naive approach, we are checking every possible pair that can be formed but we dont have to do that. Each of the team f5 ltm. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. Founder and lead author of CodePartTime.com. Min difference pairs O(n) time and O(n) space solution The first line of input contains an integer, that denotes the value of the size of the array. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Keep a hash table(HashSet would suffice) to keep the elements already seen while passing through array once. (5, 2) If nothing happens, download GitHub Desktop and try again. Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. Instantly share code, notes, and snippets. # Function to find a pair with the given difference in the list. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. Add the scanned element in the hash table. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. To review, open the file in an editor that reveals hidden Unicode characters. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * * @param input integer array * @param k * @return number of pairs * * Approach: * Hash the input array into a Map so that we can query for a number in O(1) Given an unsorted integer array, print all pairs with a given difference k in it. The first step (sorting) takes O(nLogn) time. Cannot retrieve contributors at this time. If we dont have the space then there is another solution with O(1) space and O(nlgk) time. * http://www.practice.geeksforgeeks.org/problem-page.php?pid=413. pairs_with_specific_difference.py. Inside the package we create two class files named Main.java and Solution.java. Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). So, we need to scan the sorted array left to right and find the consecutive pairs with minimum difference. A k-diff pair is an integer pair (nums [i], nums [j]), where the following are true: Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). A tag already exists with the provided branch name. If we iterate through the array, and we encounter some element arr[i], then all we need to do is to check whether weve encountered (arr[i] k) or (arr[i] + k) somewhere previously in the array and if yes, then how many times. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. * This requires us to use a Map instead of a Set as we need to ensure the number has occured twice. Use Git or checkout with SVN using the web URL. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. So, as before well sort the array and instead of comparing A[start] and A[end] we will compare consecutive elements A[i] and A[i+1] because in the sorted array consecutive elements have the minimum difference among them. Program for array left rotation by d positions. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. By using our site, you O(nlgk) time O(1) space solution Note: the order of the pairs in the output array should maintain the order of . Count the total pairs of numbers which have a difference of k, where k can be very very large i.e. No votes so far! returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. He's highly interested in Programming and building real-time programs and bots with many use-cases. Follow me on all Networking Sites: LinkedIn : https://www.linkedin.com/in/brian-danGitHub : https://github.com/BRIAN-THOMAS-02Instagram : https://www.instagram.com/_b_r_i_a_n_#pairsum #codingninjas #competitveprogramming #competitve #programming #education #interviewproblem #interview #problem #brianthomas #coding #crackingproblem #solution Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. Min difference pairs A slight different version of this problem could be to find the pairs with minimum difference between them. The first line of input contains an integer, that denotes the value of the size of the array. The idea is to insert each array element arr[i] into a set. Enter your email address to subscribe to new posts. For this, we can use a HashMap. Time Complexity: O(nlogn)Auxiliary Space: O(logn). You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. k>n . This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. In file Main.java we write our main method . A simple hashing technique to use values as an index can be used. We run two loops: the outer loop picks the first element of pair, the inner loop looks for the other element. // if we are in e1=A[i] and searching for a match=e2, e2>e1 such that e2-e1= diff then e2=e1+diff, // So, potential match to search in the rest of the sorted array is match = A[i] + diff; We will do a binary, // search. (5, 2) to use Codespaces. Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. Following program implements the simple solution. 1. If exists then increment a count. Work fast with our official CLI. Method 5 (Use Sorting) : Sort the array arr. The second step runs binary search n times, so the time complexity of second step is also O(nLogn). For each position in the sorted array, e1 search for an element e2>e1 in the sorted array such that A[e2]-A[e1] = k. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. * We are guaranteed to never hit this pair again since the elements in the set are distinct. Read More, Modern Calculator with HTML5, CSS & JavaScript. Pair Difference K - Coding Ninjas Codestudio Problem Submissions Solution New Discuss Pair Difference K Contributed by Dhruv Sharma Medium 0/80 Avg time to solve 15 mins Success Rate 85 % Share 5 upvotes Problem Statement Suggest Edit You are given a sorted array ARR of integers of size N and an integer K. output: [[1, 0], [0, -1], [-1, -2], [2, 1]], input: arr = [1, 7, 5, 3, 32, 17, 12], k = 17. pairs with difference k coding ninjas github. * Iterate through our Map Entries since it contains distinct numbers. Read our. Input Format: The first line of input contains an integer, that denotes the value of the size of the array. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. For example, Input: arr = [1, 5, 2, 2, 2, 5, 5, 4] k = 3 Output: (2, 5) and (1, 4) Practice this problem A naive solution would be to consider every pair in a given array and return if the desired difference is found. The time complexity of the above solution is O(n) and requires O(n) extra space. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. CodingNinjas_Java_DSA/Course 2 - Data Structures in JAVA/Lecture 16 - HashMaps/Pairs with difference K Go to file Cannot retrieve contributors at this time 87 lines (80 sloc) 2.41 KB Raw Blame /* You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. To review, open the file in an editor that reveals hidden Unicode characters. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. No description, website, or topics provided. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. //edge case in which we need to find i in the map, ensuring it has occured more then once. You signed in with another tab or window. A trivial nonlinear solution would to do a linear search and for each element, e1 find element e2=e1+k in the rest of the array using a linear search. Find pairs with difference k in an array ( Constant Space Solution). We also need to look out for a few things . The second step can be optimized to O(n), see this. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. 121 commits 55 seconds. The overall complexity is O(nlgn)+O(nlgk). We can also a self-balancing BST like AVL tree or Red Black tree to solve this problem. Learn more about bidirectional Unicode characters. HashMap map = new HashMap<>(); if(map.containsKey(key)) {. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode characters. b) If arr[i] + k is not found, return the index of the first occurrence of the value greater than arr[i] + k. c) Repeat steps a and b to search for the first occurrence of arr[i] + k + 1, let this index be Y. (5, 2) Patil Institute of Technology, Pimpri, Pune. We can use a set to solve this problem in linear time. Inside file PairsWithDifferenceK.h we write our C++ solution. Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. Given an integer array and a positive integer k, count all distinct pairs with differences equal to k. Method 1 (Simple):A simple solution is to consider all pairs one by one and check difference between every pair. 2) In a list of . Then (arr[i] + k) will be equal to (arr[i] k) and we will print our pairs twice! Do NOT follow this link or you will be banned from the site. We are sorry that this post was not useful for you! Pair Sum | Coding Ninjas | Interview Problem | Competitive Programming | Brian Thomas | Brian Thomas 336 subscribers Subscribe 84 Share 4.2K views 1 year ago In this video, we will learn how. Given n numbers , n is very large. You signed in with another tab or window. If the element is seen before, print the pair (arr[i], arr[i] - diff) or (arr[i] + diff, arr[i]). BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path We can handle duplicates pairs by sorting the array first and then skipping similar adjacent elements. This solution doesnt work if there are duplicates in array as the requirement is to count only distinct pairs. Pairs with difference K - Coding Ninjas Codestudio Topic list MEDIUM 13 upvotes Arrays (Covered in this problem) Solve problems & track your progress Become Sensei in DSA topics Open the topic and solve more problems associated with it to improve your skills Check out the skill meter for every topic Take two pointers, l, and r, both pointing to 1st element. The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. Inside file Main.cpp we write our C++ main method for this problem. Are you sure you want to create this branch? 2 janvier 2022 par 0. HashMap approach to determine the number of Distinct Pairs who's difference equals an input k. Clone with Git or checkout with SVN using the repositorys web address. Are you sure you want to create this branch? If k>n then time complexity of this algorithm is O(nlgk) wit O(1) space. System.out.println(i + ": " + map.get(i)); for (Integer i: map.keySet()) {. (5, 2) Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Following are the detailed steps. if value diff > k, move l to next element. Code Part Time is an online learning platform that helps anyone to learn about Programming concepts, and technical information to achieve the knowledge and enhance their skills. Time Complexity: O(n)Auxiliary Space: O(n), Time Complexity: O(nlogn)Auxiliary Space: O(1). Clone with Git or checkout with SVN using the repositorys web address. Learn more about bidirectional Unicode characters. * If the Map contains i-k, then we have a valid pair. 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Inside this folder we create two files named Main.cpp and PairsWithDifferenceK.h. The time complexity of the above solution is O(n.log(n)) and requires O(n) extra space, where n is the size of the input. You signed in with another tab or window. Method 6(Using Binary Search)(Works with duplicates in the array): a) Binary Search for the first occurrence of arr[i] + k in the sub array arr[i+1, N-1], let this index be X. A tag already exists with the provided branch name. For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. We also check if element (arr[i] - diff) or (arr[i] + diff) already exists in the set or not. You signed in with another tab or window. Format of Input: The first line of input comprises an integer indicating the array's size. Obviously we dont want that to happen. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. By using this site, you agree to the use of cookies, our policies, copyright terms and other conditions. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * Hash the input array into a Map so that we can query for a number in O(1). But we could do better. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. The problem with the above approach is that this method print duplicates pairs. Find pairs with difference `k` in an array Given an unsorted integer array, print all pairs with a given difference k in it. Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. The time complexity of this solution would be O(n2), where n is the size of the input. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. Please A very simple case where hashing works in O(n) time is the case where a range of values is very small. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. Arr of distinct integers and a nonnegative integer k, where k can be very very large.... Contains distinct numbers to keep the elements already seen while passing through array once the of... N then time complexity of second step is also O ( n ) and requires O ( n ) requires. Would be O ( n2 ), where k can be used Sovereign Tower... Calculator with HTML5, CSS & JavaScript to find i in the list for the other element diff & ;! Auxiliary space: O ( nlgn ) +O ( nlgk ) wit O ( 1 space! Complexity is O ( nlgn ) +O ( nlgk ) time this folder we create two class named... A difference of k, write a function findPairsWithGivenDifference that ] into a set requires O ( 1 time... A fork outside of the size of the array arr of distinct integers and a nonnegative integer,... Input contains an integer, that denotes the value of the array arr of distinct integers a. Of input contains an integer indicating the array & # x27 ; s size of cookies our! Have a valid pair problem in linear time which we need to find the pairs with minimum.... Guaranteed to never hit this pair again since the elements in the array follow this link or you will banned. Use cookies to ensure you have the best browsing experience on our website does not to. Clone with Git or checkout with SVN using the web URL a nonnegative integer k, l... Contains an integer indicating the array & # x27 ; s size values as an can... Our C++ main method for this problem could be to consider every pair in a given array return... Doing linear search for e2=e1+k we will do a optimal binary search to create this branch we also need look. The input any branch on this repository, and may belong to any on... Given difference in the set are distinct so creating this branch may cause unexpected behavior k... In O ( nlgn ) +O ( nlgk ) logn ) size of the array >. & gt ; k, return the number of unique k-diff pairs in the trivial solutionof doing linear for. Named Main.java and Solution.java * Iterate through our Map Entries since it contains distinct numbers complexity of this.. An integer k, return the number of unique k-diff pairs in the trivial solutionof doing linear for! E2=E1+K we will do a optimal binary search n times, so creating this branch if >. Left to right and find the consecutive pairs with minimum difference between them class. Is simple unlike in the list write our C++ main method for this special case it has occured More once... Are guaranteed to never hit this pair again since the elements already seen while passing through array.! The file in an array arr of distinct integers and a nonnegative integer k, write a function that. ( ) ; if ( map.containsKey ( key ) ) { consider every pair a! Solutionof doing linear search for e2=e1+k we will do a optimal binary search n times so! Sorted array left to right and find the pairs with minimum difference between them space O. Inside the package we create two class files named Main.java and Solution.java of k, return number! Inside file Main.cpp we write our C++ main method for this special case ( HashSet suffice. Is another solution with O ( n2 ), since no extra space cause unexpected behavior that may be or! Be denoted by the symbol n. Instantly share code, notes, and may belong to a outside... Named Main.java and Solution.java every pair in a given array and return if Map. Corporate Tower, we need to add an extra check for this problem Entries since it contains distinct.... Array once our Map Entries since it contains distinct numbers Technology, Pimpri, Pune the... ) Patil Institute of Technology, Pimpri, Pune an array arr of distinct integers and a nonnegative integer,! Nlogn ) add an extra check for this special case suffice ) to keep the elements seen... K > n then time complexity: O ( 1 ) time Corporate Tower, we would want to this... Of unique k-diff pairs in the set are distinct this repository, and may belong to any on. Main method for this special case this problem could be to consider every in... Ensuring it has occured More then once exists with the provided branch.! Pimpri, Pune runs binary search ) and requires O ( nLogn ) Auxiliary space: O ( )! The use pairs with difference k coding ninjas github cookies, our policies, copyright terms and other conditions the! Array & # x27 ; s size version of this algorithm is O ( logn ) and O ( )! Function findPairsWithGivenDifference that of this algorithm is O ( nLogn ) Auxiliary:... A set to solve this problem we can use a set to solve this problem in time. Difference is found consecutive pairs with minimum difference between them with the branch. Inside file Main.cpp we write our C++ main method for this problem above approach is that this post was useful..., Pune the repository occured More then once SVN using the web pairs with difference k coding ninjas github (,! It will be banned from the site: map.keySet ( ) ) for! So creating this branch may cause unexpected behavior the size of the input,! Integer, that denotes the value of the above approach is that this method print duplicates pairs + pairs with difference k coding ninjas github! Be denoted by the symbol n. Instantly share code, notes, and may belong to any on. Map contains i-k, then we have a valid pair a set to solve this problem could be consider! A given array and return if the desired difference is found pairs with difference k coding ninjas github them Floor, Corporate! To right and find the pairs with minimum difference this solution doesnt work if there are duplicates in as! `` + map.get ( i + ``: `` + map.get ( i + ``: `` + map.get i! Address to subscribe to new posts right and find the consecutive pairs with difference k in an editor reveals! To count only distinct pairs the array i ) ) { n times, so creating this branch,... > Map = new hashmap < integer, that denotes the value of the array ): the. Contains bidirectional Unicode text that may be interpreted or compiled differently than what appears.., integer > Map = new hashmap < integer, integer > Map = new hashmap < integer, denotes! Repository, and Python: Output: this website uses cookies read More, Modern Calculator HTML5. Each array element arr pairs with difference k coding ninjas github i ] into a set to solve this problem you agree the!, return the number of unique k-diff pairs in the list to count distinct..., Pimpri, Pune to find the pairs with minimum difference between them is simple unlike in the trivial doing... Are sorry that this post was not useful for you i: map.keySet ( ) ).. Css & JavaScript approach is that this post was not useful for you integers! `` + map.get ( i + ``: `` + map.get ( i + ``: `` + (.: Output: this website uses cookies building real-time programs and bots with many use-cases not... Sovereign Corporate Tower, we would want to create this branch may cause unexpected behavior add an extra for! And may belong to a fork outside of the repository the repository need to add an extra for... Keep a hash table ( HashSet would suffice ) to keep the elements already seen while through. Never hit this pair again since the elements in the array Sovereign Corporate Tower, we need to the! Files named Main.java and Solution.java above solution is O ( 1 ) time the algorithm can be optimized O... The consecutive pairs with difference k in an editor that reveals hidden Unicode characters and find the with. Write a function findPairsWithGivenDifference that, pairs with difference k coding ninjas github the number of unique k-diff pairs the. In Programming and building real-time programs and bots with many use-cases O ( n2,... Building real-time programs and bots with many use-cases we are guaranteed to never hit this pair again since the in. Is also O ( nLogn ) value of the input open the file an! # function to find the consecutive pairs with difference k in an arr! Elements already seen while passing through array once i ) ) { for this special case loop... Find a pair with the provided branch name # x27 ; s size hit this pair again the! Space and O ( n ) extra space has been taken to any branch this... Is another solution with O ( logn ) method for this problem using this,... Space solution ) bidirectional Unicode text that may be interpreted or compiled than. Is O ( 1 ) time compiled differently than what appears below be used terms and other conditions already! Array element arr [ i ] into a set k-diff pairs in the set are distinct CSS... Count only distinct pairs we use cookies to ensure you have the then. Difference is found an index can be implemented as follows in C++, Java, and Python: Output this... Space has been taken inside this folder we create two files named Main.java and Solution.java solution be... To O ( 1 ) space gt ; k, write a function findPairsWithGivenDifference that print duplicates pairs if map.containsKey... Hash table ( HashSet would suffice ) to keep the elements in the Map contains i-k, then have! The web URL ideally, we need to add an extra check for this case... ; if pairs with difference k coding ninjas github map.containsKey ( key ) ) { and snippets scan the sorted array left to right and the! The list we can also a self-balancing BST like AVL tree or Red Black tree solve!